Font struct

TokenstringID - Your SubAccount IDstringstatus - Status of the AccountReturn ValueintegerReturn Update Statusmethod surveyColorUpdateUpdate Survey Color based on the details provided. Return the ID of the Survey.Parametersstringtoken - Your Benchmark Email TokenstringSurveyID - Survey ID of the surveystruct SurveyColorStructuresurveyColor - The details for the SurveyColorReturn ValuestringReturns the ID of the Survey.method surveyColorUpdateDetailUpdate Survey Color based on the details provided. Return the ID of the Survey.Parametersstringtoken - Your Benchmark Email Tokenstringdata - The details for the SurveyColorReturn ValuestringReturns the ID of the Survey.method surveyCopyCopy an existing survey to new SurveyParametersstringtoken - Your Benchmark Email TokenstringSurveyID - ID of the existing surveystringNewSurveyName - Name of the new SurveyReturn ValuestringReturns the id of newly created Survey.method surveyCopyTemplateCopy an existing survey Template to new SurveyParametersstringtoken - Your Benchmark Email TokenstringTemplateID - ID of the existing surveystringNewSurveyName - Name of the new SurveyReturn ValuestringReturns the id of newly created Survey.method surveyCreateCreate a new Survey based on the details provided. Return the ID of the newly created Survey.Parametersstringtoken - Your Benchmark Email Tokenstruct SurveyStructuresurvey - The details for the SurveyReturn ValuestringReturns the ID of the newly created Survey.method surveyDeleteDelete an existing Survey based on the information provided.Parametersstringtoken - Your Benchmark Email TokenstringSurveyID - ID of the survey which is to be deletedReturn ValuestringReturns the ID of deleted Survey.method surveyGetColorGet the Colors and font styles of the surveyParametersstringtoken - Your Benchmark Email TokenstringSurveyID - The survey id of the surveyReturn Valuestruct SurveyColorStructureReturns the Colors of the surveymethod surveyGetDetailGet the survey details.Parametersstringtoken - Your Benchmark Email TokenstringsurveyID - survey idstringlanguage - languageReturn ValueReturns the survey details.method surveyGetListGet the list of Surveys using the filter and paging limits, order by the name or date of the surveys.Parametersstringtoken - Your Benchmark Email Tokenstringfilter - The filter you want to apply when fetching the surveystringstatus - The status of the surveyintegerpageNumber - The page number from which you want the listintegerpageSize - The number of results per pagestringorderBy - The field you want to order by (list / date)stringsortOrder - The sort order (asc / desc)Return Valuearray of struct SurveyStructureReturns the list of surveys.method surveyGetQuestionListGet the list of Survey QuestionsParametersstringtoken - Your Benchmark Email TokenstringSurveyID - The survey id of the surveyReturn Valuearray of struct SurveyQuestionStructureReturns the list of surveys.method surveymonkeyGetLinkListGet the list of links in a survey for Survey MonkeyParametersstringtoken - Your Benchmark Email TokenstringsurveyID - Survey IDReturn Valuearray of struct ImageStructureReturns the list links of Survey s.method surveymonkeyGetListGet the list of survey's in Survey MonkeyParametersstringtoken - Your Benchmark Email TokenReturn Valuearray of struct ImageStructureReturns the list of Survey s.method surveyQuestionCreateCreate a new Survey Question based on the details provided. Return the ID of the newly created Survey Question.Parametersstringtoken - Your Benchmark Email TokenstringSurveyID - ID of the survey for

Nodes.6. ENDExampleFollowing are the implementations of this operation in various programming languages − #include #include struct node { int data; struct node *leftChild, *rightChild;};struct node *root = NULL;struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->data = item; temp->leftChild = temp->rightChild = NULL; return temp;}void insert(int data){ struct node *tempNode = (struct node*) malloc(sizeof(struct node)); struct node *current; struct node *parent; tempNode->data = data; tempNode->leftChild = NULL; tempNode->rightChild = NULL; //if tree is empty if(root == NULL) { root = tempNode; } else { current = root; parent = NULL; while(1) { parent = current; //go to left of the tree if(data data) { current = current->leftChild; //insert to the left if(current == NULL) { parent->leftChild = tempNode; return; } }//go to right of the tree else { current = current->rightChild; //insert to the right if(current == NULL) { parent->rightChild = tempNode; return; } } } }}void printTree(struct node* Node){ if(Node == NULL) return; printTree(Node->leftChild); printf(" --%d", Node->data); printTree(Node->rightChild);}int main(){ insert(55); insert(20); insert(90); insert(50); insert(35); insert(15); insert(65); printf("Insertion done\n"); printf("BST: \n"); printTree(root); return 0;}OutputInsertion doneBST: --15 --20 --35 --50 --55 --65 --90 #include using namespace std;struct node { int data; struct node *leftChild, *rightChild;};struct node *root = NULL;struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->data = item; temp->leftChild = temp->rightChild = NULL; return temp;}void insert(int data){ struct node *tempNode = (struct node*) malloc(sizeof(struct node)); struct node *current; struct node *parent; tempNode->data = data; tempNode->leftChild = NULL; tempNode->rightChild = NULL; //if tree

Subtree is printed first, followed by the right subtree and lastly, the root node.Algorithm1. START2. Traverse the left subtree, recursively3. Traverse the right subtree, recursively.4. Then, traverse the root node5. ENDExampleFollowing are the implementations of this operation in various programming languages − #include #include struct node { int key; struct node *left, *right;};struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->key = item; temp->left = temp->right = NULL; return temp;}// Postorder Traversalvoid postorder(struct node *root){ if (root != NULL) { printf("%d -> ", root->key); postorder(root->left); postorder(root->right); }}// Insertion operationstruct node *insert(struct node *node, int key){ if (node == NULL) return newNode(key); if (key key) node->left = insert(node->left, key); else node->right = insert(node->right, key); return node;}int main(){ struct node *root = NULL; root = insert(root, 55); root = insert(root, 20); root = insert(root, 90); root = insert(root, 50); root = insert(root, 35); root = insert(root, 15); root = insert(root, 65); printf("Postorder traversal: "); postorder(root);}OutputPostorder traversal: 55 -> 20 -> 15 -> 50 -> 35 -> 90 > 65 -> #include struct node { int key; struct node *left, *right;};struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->key = item; temp->left = temp->right = NULL; return temp;}// Postorder Traversalvoid postorder(struct node *root){ if (root != NULL) { printf("%d -> ", root->key); postorder(root->left); postorder(root->right); }}// Insertion operationstruct node *insert(struct node *node, int key){ if (node == NULL) return newNode(key); if (key key) node->left = insert(node->left, key); else node->right = insert(node->right, key); return node;}int main(){ struct

A Binary Search Tree visits all its nodes. However, the root node in it is first printed, followed by its left subtree and then its right subtree.Algorithm1. START2. Traverse the root node first.3. Then traverse the left subtree, recursively4. Later, traverse the right subtree, recursively.5. ENDExampleFollowing are the implementations of this operation in various programming languages − #include #include struct node { int key; struct node *left, *right;};struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->key = item; temp->left = temp->right = NULL; return temp;}// Preorder Traversalvoid preorder(struct node *root){ if (root != NULL) { printf("%d -> ", root->key); preorder(root->left); preorder(root->right); }}// Insertion operationstruct node *insert(struct node *node, int key){ if (node == NULL) return newNode(key); if (key key) node->left = insert(node->left, key); else node->right = insert(node->right, key); return node;}int main(){ struct node *root = NULL; root = insert(root, 55); root = insert(root, 20); root = insert(root, 90); root = insert(root, 50); root = insert(root, 35); root = insert(root, 15); root = insert(root, 65); printf("Preorder traversal: "); preorder(root);}OutputPreorder traversal: 55 -> 20 -> 15 -> 50 -> 35 -> 90 -> 65 -> #include struct node { int key; struct node *left, *right;};struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->key = item; temp->left = temp->right = NULL; return temp;}// Preorder Traversalvoid preorder(struct node *root){ if (root != NULL) { printf("%d -> ", root->key); preorder(root->left); preorder(root->right); }}// Insertion operationstruct node *insert(struct node *node, int key){ if (node == NULL) return newNode(key); if

= res->next; } out += sprintf(out, "assigned resources: IO\n"); index = 11; res = new_slot->io_head; while (res && index--) { out += sprintf(out, "start = %8.8x, length = %8.8x\n", res->base, res->length); res = res->next; } out += sprintf(out, "assigned resources: bus numbers\n"); index = 11; res = new_slot->bus_head; while (res && index--) { out += sprintf(out, "start = %8.8x, length = %8.8x\n", res->base, res->length); res = res->next; } slot = slot->next; } return out - buf;}static int spew_debug_info(struct controller *ctrl, char *data, int size){ int used; used = size - show_ctrl(ctrl, data); used = (size - used) - show_dev(ctrl, &data[used]); return used;}struct ctrl_dbg { int size; char *data; struct controller *ctrl;};#define MAX_OUTPUT (4*PAGE_SIZE)static int open(struct inode *inode, struct file *file){ struct controller *ctrl = inode->i_private; struct ctrl_dbg *dbg; int retval = -ENOMEM; mutex_lock(&cpqphp_mutex); dbg = kmalloc(sizeof(*dbg), GFP_KERNEL); if (!dbg) goto exit; dbg->data = kmalloc(MAX_OUTPUT, GFP_KERNEL); if (!dbg->data) { kfree(dbg); goto exit; } dbg->size = spew_debug_info(ctrl, dbg->data, MAX_OUTPUT); file->private_data = dbg; retval = 0;exit: mutex_unlock(&cpqphp_mutex); return retval;}static loff_t lseek(struct file *file, loff_t off, int whence){ struct ctrl_dbg *dbg = file->private_data; return fixed_size_llseek(file, off, whence, dbg->size);}static ssize_t read(struct file *file, char __user *buf, size_t nbytes, loff_t *ppos){ struct ctrl_dbg *dbg = file->private_data; return simple_read_from_buffer(buf, nbytes, ppos, dbg->data, dbg->size);}static int release(struct inode *inode, struct file *file){ struct ctrl_dbg *dbg = file->private_data; kfree(dbg->data); kfree(dbg); return 0;}static const struct file_operations debug_ops = { .owner = THIS_MODULE, .open = open, .llseek = lseek, .read = read, .release = release,};static struct dentry *root;void cpqhp_initialize_debugfs(void){ if (!root) root = debugfs_create_dir("cpqhp", NULL);}void cpqhp_shutdown_debugfs(void){ debugfs_remove(root);}void cpqhp_create_debugfs_files(struct controller *ctrl){ ctrl->dentry = debugfs_create_file(dev_name(&ctrl->pci_dev->dev), S_IRUGO, root, ctrl, &debug_ops);}void cpqhp_remove_debugfs_files(struct controller *ctrl){ debugfs_remove(ctrl->dentry); ctrl->dentry = NULL;}

54 Inorder TraversalThe inorder traversal operation in a Binary Search Tree visits all its nodes in the following order −Firstly, we traverse the left child of the root node/current node, if any.Next, traverse the current node.Lastly, traverse the right child of the current node, if any.Algorithm1. START2. Traverse the left subtree, recursively3. Then, traverse the root node4. Traverse the right subtree, recursively.5. ENDExampleFollowing are the implementations of this operation in various programming languages − #include #include struct node { int key; struct node *left, *right;};struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->key = item; temp->left = temp->right = NULL; return temp;}// Inorder Traversalvoid inorder(struct node *root){ if (root != NULL) { inorder(root->left); printf("%d -> ", root->key); inorder(root->right); }}// Insertion operationstruct node *insert(struct node *node, int key){ if (node == NULL) return newNode(key); if (key key) node->left = insert(node->left, key); else node->right = insert(node->right, key); return node;}int main(){ struct node *root = NULL; root = insert(root, 55); root = insert(root, 20); root = insert(root, 90); root = insert(root, 50); root = insert(root, 35); root = insert(root, 15); root = insert(root, 65); printf("Inorder traversal: "); inorder(root);}OutputInorder traversal: 15 -> 20 -> 35 -> 50 -> 55 -> 65 -> 90 -> #include struct node { int key; struct node *left, *right;};struct node *newNode(int item){ struct node *temp = (struct node *)malloc(sizeof(struct node)); temp->key = item; temp->left = temp->right = NULL; return temp;}// Inorder Traversalvoid inorder(struct node *root){ if (root != NULL) { inorder(root->left); printf("%d -> ", root->key);